![]() ![]() Well I hope you can help me I've looked for information in the web by some days and I couldn't solve the problem. Make: *** Error 1ġ9:56:58: The process "/usr/bin/make" exited with code 2.Įrror while building/deploying project find (kit: Desktop Qt 5.4.2 clang 64bit) Ld: symbol(s) not found for architecture x86_64Ĭlang: error: linker command failed with exit code 1 (use -v to see invocation) "FindDialog::enableFindButton(QString const&)", referenced from:įindDialog::qt_static_metacall(QObject*, QMetaObject::Call, int, void**) in moc_finddialog.o Undefined symbols for architecture x86_64: Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang++ -headerpad_max_install_names -Wl,-syslibroot,/Applications/Xcode.app/Contents/Developer/Platforms/atform/Developer/SDKs/MacOSX10.10.sdk -mmacosx-version-min=10.7 -Wl,-rpath,/Applications/Qt/5.4/clang_64/lib -o find.app/Contents/MacOS/find finddialog.o main.o moc_finddialog.o -F/Applications/Qt/5.4/clang_64/lib -framework QtWidgets -framework QtGui -framework QtCore -framework DiskArbitration -framework IOKit -framework OpenGL -framework AGL The output is this 19:56:55: Running steps for project find.ġ9:56:55: Configuration unchanged, skipping qmake step. QHBoxLayout *mainLayout = new QHBoxLayout ĬaseCheckBox->isChecked() ?Qt::CaseSensitive QVBoxLayout *rigthLayout = new QVBoxLayout QVBoxLayout *leftLayout = new QVBoxLayout QHBoxLayout *topLeftLayout = new QHBoxLayout Void enableFindButton(const QString &text) ĬaseCheckBox = new QCheckBox(tr("Match &case")) īackwardCheckBox = new QCheckBox(tr("Search &backward")) įindButton = new QPushButton(tr("&Find")) ĬloseButton = new QPushButton(tr("Close")) Ĭonnect(lineEdit, SIGNAL(textChanged(const QString &)),this, SLOT(enableFindButton(QString))) Ĭonnect(findButton, SIGNAL(clicked()),this, SLOT(findClicked())) Ĭonnect(closeButton, SIGNAL(clicked()),this, SLOT(close())) Void findPrevious(const QString &str, Qt::CaseSensitivity cs) Void findNext(const QString &str, Qt::CaseSensitivity cs) This is my finddialog.h #ifndef FINDDIALOG_H GreaterThan(QT_MAJOR_VERSION, 4): QT += widgets I just get 2 errors: :-1: error: symbol(s) not found for architecture x86_64, :-1: error: linker command failed with exit code 1 (use -v to see invocation) I'm using Qt 5.4 in Mac OS X Yosemite 10.10.4. Now I have problems when I try to compile my code. I'm doing my first baby steps following this book: "C++ GUI Programming with Qt 4". Ownership, while like above not relevant for access to the file pointed to by the symlink on most systems, can have some other relevance wrt the t bit of the parent directory or quotas.Well. On systems where symlink permissions matter (like OS/X where you need read permission to a symlink to be able to resolve its target), there's generally a way to change them ( chmod -h on OS/X). mold is designed to increase developer productivity by reducing build time, especially in rapid debug-edit-rebuild cycles. It is several times faster than the LLVM lld linker, the second-fastest open-source linker which I originally created a few years ago. On most systems, permissions on symlinks are ignored and generally fixed to rwxrwxrwx. mold: A Modern Linker mold is a faster drop-in replacement for existing Unix linkers. Portably, your best option is to remove the link first and then recreate it: rm -f link & ln -s new/target link Documentation for compiler flags is available in the GCC manual.Those flags (which start with -Wl) are passed to the linker and are described in the documentation for ld. bss section, under the assumption that these historic features have been phased out by now. It works like -T except when link is actually a real directory in which case it will still create the symlink inside that directory (instead of failing with an error). This table does not list flags for managing an executable stack or the. ![]() Like before, it will remove the original link symlink and create it anew with new/target as the target (and the process' euid and egid as the owner). To overcome that, GNU ln has a -T option for the link name to always be considered as link name, and not as a directory to create the link(s) in. So you'll actually create a: foo/bar/target -> new/target That's understood as creating a new target symlink inside the link directory ( link is a directory because it's a symlink to the foo/bar directory). In that case, when you do: ln -s new/target link Will fail because link already exists, but you can overcome that by using the standard: ln -fs new/target linkįoo/bar is a directory (and you have search permission to foo to be able to determine that foo/bar is a directory). When you have a link like: link -> foo/barĪnd want to change it to: link -> new/targetįoo/bar is not a directory or doesn't exist or you don't have search access to foo. ![]()
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